What is the number of triangles that can be formed whose vertices are the vertices of an octagon but have only one side common with that of octagon?
For one vertex 4triangles ...end triangles against the condition
So, you take one side at a time and draw all the possible triangles with that side. Each side will give a maximum of 4 triangles. Octagon has 8 sides, so 8 x 4 = 32. Bingo!
Well Manu, I think that is correct. But let us have how you will get to this answer?